MODULE
1
Inorganic
Chemistry
7.2.1. Redox
Oxidation and reduction in terms of electron transfer. The concept and use of oxidation
numbers. The idea that the oxidation
number of an element changes in a redox reaction.
Oxidation and
Reduction
Oxidation was originally definedas the gaining of oxygen or the loss of hydrogen from an element or compound. Reduction was the reverse of this.
PbO + CO
Pb
+ CO2
2H2S + O2
2H2O + 2S
N.B. When oxidation takes place in a chemical reaction reduction will also take place at the same time in the reaction - hence the term redox (for reduction and oxidation).
The present view of redox is that involving electron transfer.
Oxidation involves a loss of electrons
Reduction involves a gain of electrons.
(Remember
L.E.O. or O.I.L.R.I.G.)
OXIDATION
Sn2+ +
2Fe3+
Sn4+ +
2Fe2+
REDUCTION
The Sn2+ has lost 2 electrons and is therefore oxidized.
Sn2+
Sn4+
+ 2e-
The Sn2+ is the electron donor or REDUCING AGENT.
Each Fe3+ has gained an electron and is therefore reduced.
Fe3+ + e-
Fe2+
The Fe3+ is the electron acceptor or OXIDIZING AGENT .
EXERCISE. 1 Complete the following:
OXIDATION
Fe + Cu2+
Fe2+ + Cu
REDUCTION
Cu2+ is the agent
Fe is the agent
2Mg + O2
2Mg2+ + O2-
O2 is the agent
Mg is the agent
Oxidation Number
These can provide a useful guide to the extent of oxidation or reduction in a species.
Oxidation numbers are determined as follows:
1. The oxidation numbers of monatomic ions are the charges on the ions
|
ion |
Na+ |
Cl- |
Fe3+ |
S2- |
|
|
Ox. Num. |
+1 |
-1 |
+3 |
-2 |
|
2. For non-ionic compounds the following rules may be applied.
A Elements have oxidation numbers of zero (0)
B Hydrogen is generally +1 in its compounds except when joined to a metal e.g. NaH when it is -1
NaH
Ox. Num. +1 -1
C Oxygen is generally -2 in its compounds, except for H2O2 (where Ox. Num. is -1) and F2O (where Ox. Num. is +2).
D In neutral molecules the sum of the Ox. Num.'s is zero and in ions the sum of the Ox. Num.'s is the same as the chargew on the ion.
|
|
CH4 |
NO2 |
SO42- |
NH4+ |
|
Ox. Num. |
-4 +1 |
+4 -2 |
+6 -2 |
-3 +1 |
E In a compound the more electronegative atom has the negative oxidation number and the less electronegative atom has the positive oxidation number.
F2 + 1/2O2
F2O
Ox. Num. 0 0 -1 +2
EXERCISE. 2 Add oxidation numbers to complete the following:
|
|
NaCl |
HCl |
CaCl2 |
Al2O3 |
CO |
|
Ox. Num. |
|
|
|
|
|
|
|
CO2 |
NaOH |
OH- |
MnO4- |
Cr2O72- |
|
Ox.Num. |
|
|
|
|
|
Oxidation occurs when the oxidation number is increased (or becomes less negative).
reduction occurs when the oxidation number is decreased (or becomes more negative).
S
+ O2
SO2
Ox. Num. 0 0 +4 -2
The oxidation number of S has increased from 0 to +4 (i.e. it has been oxidized) while the oxidation number of O has decreased from 0 to -2 (i.e. it has been reduced).
EXERCISE. 3 Show using oxidation numbers whether the following is a redox reaction or not.
SO2 + OH-
HSO3-
Balancing of redox equations from given half equations and for
reactions where the reactants and products are specified (omitting spectator
ions).
Redox Reactions
Many chemicals in aqueous solution are oxidizing agents (e.g. MnO4-, Cr2O72-, Cl2, Fe3+ etc.) while others are reducing agrents (e.g. SO32-, Sn2+, Fe2+ etc.).
It is therefore possible to have many redox reactions involving combinations of any pair of oxidant and reductant.
To balance these types of reactions the following procedure should be adopted.
1. Write down the half equations for the oxidation and reduction reactions, including electrons.
2. Adjust half equations so that the electrons lost = electrons gained.
3. Add half equations together cancelling where appropriate.
e.g. Reaction between Fe3+ and I- ions in solution.
1. Fe3+ + e-
Fe2+
2I-
I2 + 2e-
2. 2Fe3+ + 2e-
2Fe2+
2I-
I2 + 2e-
3. 2Fe3+ + 2I-
2Fe2+ + I2
Oxidizing Action of KMnO4 and K2Cr2O7 in acid solution
A KMnO4
Reaction between KMnO4 and Na2SO3 in acid conditions.
1. MnO4- + 8H+ +5e-
Mn2+ + 4H2O
(purple) (colourless)
SO32- + H2O
SO42- + 2H+ + 2e-
2. 2MnO4- + 16H+ + 10e-
2Mn2+ + 8H2O
5SO32- +
5H2O
5SO42- +
10H+ + 10e-
3. 2MnO4- + 5SO32- + 6H+
2Mn2+ + 5SO42- + 3H2O
K2Cr2O7
Reaction between K2CrO7 and H2S in acid conditions.
1. CrO72- + 14H+
+ 6e-
2Cr3+ + 7H2O
(orange) (green)
H2S
S
+ 2H+ + 2e-
2. CrO72- + 14H+ + 6e-
2Cr3+ + 7H2O
3H2S
3S
+ 6H+ + 6e-
3. CrO72- + 8H+ + 3H2S
2Cr3+ +
3S + 7H2O
The use of standard redox potentials as a means of predicting the
feasibility of reactions (no formal treatment of cells or the hydrogen
electrode is required in this module).
Standard Electrode Potential E¿

When a metal is placed in a solution of its ions an equilibrium is established between the tendency of the metal to loose electrons and pass into solution as ions, and the opposing tendency for the ions in solution to gain electrons and be deposited on the metal.
M (s)
Mn+
(aq) + ne-
The metal aquires an electrical charge (usually negative) and a potential difference is set up between the metal and the solution called the electrode potential of the metal.
The size of this electrode potential will depend on the position of this equilibrium and this depends on;
1. the metal concerned
2. the concentration of the metal ion in solution
3. temperature
The temperature and concentration are therefore standardised at 25oC and 1 molar respectively. Under these conditions the electrode potential is known as the standard electrode potential, E¿. (For a gas/gas ion equilibrium the gas pressure is standardised as 1 atmosphere).
E¿ is in volts at 298K
By convention standard electrode potentials are written as
oxidised state + ne-
reduced state
i.e. as reduction potentials. The voltage produced is for the reaction as written, left to right.
Predicting the
Feasibility of Reactions
A table of standard
redox potentials can be used to predict the likelyhood that a reaction will
take place.
Positive E¿ values indicate systems that have a tendency to gain electrons (i.e. oxidising agents). Negative E¿ values indicate systems with a tendency to lose electrons (i.e. reducing agents).
1. Reaction of Fe2+ (aq) with halogens
2Fe2+ + Cl2
2Fe3+ + 2Cl-
E¿
2Fe2+
2Fe3+ + 2e- -0.77volts
Cl2 + 2e-
2Cl- +1.36volts
2Fe2+ + Cl2
2Fe3+ + 2Cl- +0.59volts
Overall the value of E¿ is +ve so the reaction will take place.
• Predict the feasibility of Fe2+ (aq) reacting with Br2 and I2.