1.3   Bonding

 

Section A

 

For each of the questions only one of the lettered responses (A - D) is correct.

 

Select the correct response in each case and mark its code letter by connecting the dots as illustrated on the answer sheet.

 

1.     In which one of the following pairs have the compounds the same type of bonding and shape.

          A  BF3 and NH3

          $B   CH4 and SiCl4

          C   HCl and H2O

          D  CO2 and SiO2

 

2.  Which one of the following is the correct description of the shape of the NH3 molecule?

          A      trigonal planar

          B      tetrahedral

          C      square planar

          @D      pyramidal

 

3.  Which one of the following pairs of molecules has similar bond angles?

          A  C2H4 and BF3

          B   H2O and CO2

          C   BeCl2 and CH4

          D  SF6 and C2H6

 

4.  In which one of the following pairs do both compounds contain tetrahedral bond angles between atoms?

          A BeCl2 and BCl3

          B   CCl4 and CH4

          C   SF6 and H2S

          D NH3 and H2O

 

 

 


Section B

 

1. The shapes of covalent molecules can be explained using the electron pair repulsion theory.

(a)         Draw the shapes of the following molecules.

     methane                                              tetrahedral (2) 

    

 

 

                                                                                                                                           [2]

     water

bent or V-shaped (2)

 

 

 

 

 

                             [2]

     carbon dioxide

linear (2)

 

 

 

 

 

     [2]

 

 

(b)    Using methane, water and carbon dioxide describe the principles of the electron pair repulsion theory and how it explains their shape. (Up to 2 marks may be obtained for the quality of written communication in this part).

 

Covalent bonds contain electron pairs (1)/ positioned around central atom (1)/ electron pairs repel each other (1)/ repulsions decrease in order lone pair:lone pair~lone pair: bond pair~bond pair:bond pair (1)/In methane all bond pairs therefore all angles equal (1)/ In water, lone pairs repel bond pairs hence bent molecule (1)/ In CO2 pairs as far apart as possible (1)                                                          ANY SIX FROM SEVEN                                           Quality of written communication (2)                                                                                                                                                                                                             

                                                                                                                                                                                                                                                                                                              [8]

 

 

(c)         Using the electron pair repulsion theory draw a possible shape for PF3.

  Explain your reasoning.

 

 

 

Trigonal pyramidal

 

 

Phosphorus, when bonded, has a full octet of electrons arranged tetrahedrally (1)/ three pairs bond to fluorine (1)/ the fourth is a lone pair (1)/ repulsion between lone pair:bond pair greater than that between bond pair:bond pair (1)                                                                                                                                                                                                                                                                                                                         [5]

 

 

2.  Beryllium occurs to a small extent in the earth's crust.  It is a steel-grey metal, which is extremely light. 

Draw and explain the shape of beryllium chloride using the electron pair repulsion theory.

 

Shape

 

 

 

 

 

 

Explanation

                                                                                                                                                                                                                                  [5]

 

 

3.    Sulphur burns in fluorine to form sulphur hexafluoride.  Draw the shape of the molecule and explain it in terms of electron pair repulsion theory.

 

 

 

 

 

 

                                                                                                      

                                                                                                 [3]