KINETICS OF THE REACTION BETWEEN SODIUM THIOSULPHATE AND HYDROCHLORIC ACID.
The purpose of this experiment is to determine the rate equation for the reaction between sodium thiosulphate and hydrochloric acid by determining the order of reaction with respect to sodium thiosulphate and hydrochloric acid.
Sodium thiosulphate and hydrochloric acid react according to the stoichiometric equation
Na2S2O3 (aq) +
2HCl (aq) 2NaCl
(aq) +
H2O (l) + SO2 (aq) + S
(s)
The
rate equation for the reaction is in the form
Rate = k [Na2S2O3]s
[HCl]t
Where
k is the rate constant
s is the order of reaction with
respect to sodium thiosulphate and t is the order of reaction with respect to
hydrochloric acid.
You
will be determining the order of reaction for each reactant by varying the
concentration of each species in turn, keeping the others constant.
The
reaction can be followed using the precipitated sulphur which causes the
solution to become opaque. The rate can
be determined by measuring the time taken for a line drawn on a piece of paper
and placed under the reaction vessel to become obscured.
Apparatus Chemicals
3 x
50 ml burettes 0.2M
sodium thiosulphate solution
2 x
100ml beakers 1M
hydrochloric acid
0-100
oC thermometer distilled
water
stop
clock
glass
stirring rod
A Varying the concentration of Na2S2O3
1 Set up three burettes in stands for hydrochloric acid, sodium thiosulphate and distilled water.
2
Add
10 cm3 of the hydrochloric acid solution to a 100 cm3
beaker labelled X.
3 In a separate beaker (Y) place 30 cm3 of the sodium thiosulphate solution and 10 cm3 of water.
4
Draw
a line on a piece of paper and place beaker Y over it
5
At
a convenient time pour the acid from beaker X into beaker Y and start a stop
clock.
6
Stir
the solution well with a glass rod and watch the line through the solution in
beaker Y.
7
Stop
the clock when the line on the paper just disappears.
8
Record
the time and the temperature of the mixture in the results table.
9
Repeat
the procedure for the rest of the mixtures in the table below.
|
Beaker X |
|
Beaker Y |
|
|
Volume of HCl /cm3 |
|
Volume of Na2S2O3
/cm3 |
Volume of water /cm3 |
|
10 |
|
30 |
10 |
|
10 |
|
25 |
15 |
|
10 |
|
20 |
20 |
|
10 |
|
15 |
25 |
|
10 |
|
10 |
30 |
|
10 |
|
5 |
35 |
10 Complete the results table.
|
Volume of Na2S2O3 /cm3 |
30 |
25 |
20 |
15 |
10 |
5 |
|
Time /s |
|
|
|
|
|
|
|
1/Time s-1 |
|
|
|
|
|
|
|
Temperature /oC |
|
|
|
|
|
|
|
Average temperature of solutions = oC |
||||||
1
Follow
a similar procedure to that for part A, but keep the volume of thiosulphate
solution constant at 10.0 cm3 and vary the volume of hydrochloric
acid as shown in the table below.
|
Beaker X |
|
Beaker Y
|
|
|
Volume of HCl /cm3 |
|
Volume of Na2S2O3
/cm3 |
Volume of water /cm3 |
|
30 |
|
10 |
10 |
|
25 |
|
10 |
15 |
|
20 |
|
10 |
20 |
|
15 |
|
10 |
25 |
|
10 |
|
10 |
30 |
|
5 |
|
10 |
35 |
2 Complete the results table below.
|
Volume of HCl /cm3 |
30 |
25 |
20 |
15 |
10 |
5 |
|
Time /s |
|
|
|
|
|
|
|
1/Time s-1 |
|
|
|
|
|
|
|
Temperature /oC |
|
|
|
|
|
|
|
Average temperature of solutions = oC |
||||||
·
For
parts A and B, plot separate graphs of 1/Time against volume of reactant under
consideration.
1/Time is proportional to the rate of reaction and
the volume of reactant is proportional to the concentration, since the total
volume is constant.
·
Deduce
from each graph whether the reaction is first order with respect to the
reactant under consideration.
·
If
you think the reaction is not first order, plot another graph, as explained
below.
Suppose that for reactant A
Rate = k1[A]n
Under the conditions of the experiment, it follows
that
1/Time = k2 Vn (where V is the initial volume of reactant)
\log (1/Time) = nlog V +
log k2
This is the equation for a straight line of the form
y = mx + c
Plotting a graph of log (1/Time) against log V
should give a straight line of slope n.
1.
Write
the rate equation for the reaction.
2.
What
is the overall order of reaction?
3.
Compare
the rate equation with the stoichiometric equation for the reaction. What is the main difference between the
two? How do you explain this
difference?
4.
How
would you calculate the rate constant for this reaction?
5.
What
are the main sources of error in this experiment?