7.5.2 Transition elements
General
characteristics such as incomplete d-shell, metallic nature, variable oxidation
states, catalytic action, formation of coloured aqua and other complexes.
The ten elements from Scandium to Zinc form the first transition metal
series. They closely resemble each
other and are hard, dense, shiny metals with high melting and boiling points. They readily form alloys and have other
properties in common. Crossing the
period from Sc to Zn there is a small decrease in atomic radius and increase in
electronegativity and ionisation energy.
Most of the properties of transition metals are related to their
electronic structures.
Transition elements are characterised
by having a partially filled d sub-shell
Sc [Ar]
3d1 4s2
Ti [Ar]
3d2 4s2
V [Ar]
3d3 4s2
*Cr [Ar]
3d5 4s1
Mn [Ar]
3d5 4s2
Fe [Ar]
3d6 4s2
Co [Ar]
3d7 4s2
Ni [Ar]
3d8 4s2
*Cu [Ar]
3d10 4s1
Zn [Ar]
3d10 4s2
*Note that in Cr the arrangement [Ar]
3d5 4s1 with half-filled 3d and 4s sub-shells is more
stable than [Ar] 3d4 4s2.
In Cu [Ar] 3d10 4s1
with a completely filled 3d sub-shell and a half-filled 4s sub-shell is more
stable than [Ar] 3d9 4s2.
Transition metals form ions which are
characterised by having a partially filled d sub-shell. The common oxidation states are
Sc 3
Ti 2 3
Cr 2 3 6
Mn 2 3 4 6 7
Fe 2 3
Co 2 3
Ni 2 3
Cu 1 2
Zn 2
Sc and Zn are not typical transition
metals as they only have one oxidation state which does not have a partially
filled d sub-shell. (Sc3+ [Ar],
Zn2+ [Ar] 3d10).
Common oxidation states are +2 and +3,
with the +2 state more common towards the end.
The higher oxidation states are shown in compounds with electronegative
elements like O, Cl or F (e.g. Cr2O72- [+6],
MnO4- [+7]).
Variable oxidation state is found
because of the small difference in energy between the 3d and 4s
sub-shells. This allows varying numbers
of electrons to be used in bonding.
When forming ions transition metals lose electrons from the 4s sub-shell
before the 3d.
e.g. Fe2+ [Ar] 3d5 (NOT [Ar] 3d4 4s2)
Ni3+ [Ar] 3d7
Cr3+ [Ar] 3d3
Mn2+ [Ar] 3d5
The ability of transition metals to
exist in various oxidation states makes them important industrial and
biological catalysts.
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|
Contact process for the manufacture
of sulphuric acid. 2SO2 +
O2
2SO3 |
|
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Haber Process for manufacturing
ammonia N2 +
3H2
2NH3 |
|
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Manufacture of nitric acid from
ammonia. 4NH3 +
5O2
4NO + 6H2O then NO NO2 HNO3 |
|
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Hydrogenation of alkenes CnH2n +
H2
CnH2n+2 |
Trace amounts of transition metals are
needed for the catalytic activity of some enzymes e.g. Cu for cytochrome oxidase (needed for
metabolism).
These are composed of a central metal
atom or ion surrounded by a number of
oppositely charged anions or neutral molecules called ligands. The ligands donate lone pairs of electrons
into the vacant d-orbitals of the transition metal atom or ion forming dative
covalent bonds
Most transition metal compounds are
coloured. In an isolated atom or ion
the 3d orbitals have the same energy (degenerate). In a complex ion the d orbitals are split due to different
overlapping with ligands.
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2
orbitals of higher energy
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DE
3 orbitals of lower energy
Transitions between the two levels will absorb energy of frequency n where DE = hn. For
the transition metals this occurs in the visible part of the spectrum, making
the ion coloured.

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absorbance
l violet blue green
yellow red
The colour of the ion is complementary
to the colour absorbed. i.e. yellow/
green absorbed -ion appears blue/ violet.
The colour of the ion depends mainly on the transition metal but can be
affected by different ligands.
Experimental
study of oxidation states of vanadium , use of redox potentials to predict
suitable reductants for the successive reduction of VO3- to VO2+,
V3+, V2+ and suitable oxidants for the
successive oxidation of V2+
to V3+, VO2+ and VO2+; the colours associated with these
oxidation states of vanadium.
[See Practical
work on the oxidation states of vanadium.]
The range of
oxidation states of vanadium can be shown by shaking a solution containing
vanadium (V) with zinc and dilute sulphuric acid. The yellow solution changes gradually through green (a mixture of
the original vanadium (V) solution and vanadium (IV) ) to blue, then to green
and finally to violet.
Oxidation state
|
+5 |
+4 |
+3 |
+2 |
|
Colour |
Yellow |
Blue |
Green |
Violet |
|
Ion |
VO2+ |
VO2+ |
V3+ |
V2+ |
The
use of transition metals as heterogeneous catalysts, such as nickel in the
hydrogenation of C=C double bonds. The
action of transition element ions with variable oxidation states as catalysts. Illustrated by the catalysis of the
decomposition of OCl- ions
to O2 by Co2+.
The ability of
transition elements to vary their oxidation state makes them very useful as
heterogeneous catalysts. The catalyst provides a surface on which the reacting
molecules can come into intimate contact and also lowers the activation energy
barrier to reaction. (See kinetics notes)
e.g. C=C
+ H2 H-C-C-H
H2 C=C
C=C H2
H2 H2 H-C-C-H
C=C
H2
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C=C H2 C=C H2 C=C H2 H-C-C-H
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absorption reaction desorption
The decomposition
of chlorate(I) ions OCl- is catalysed by addition of Co2+
ions
OCl- ½ O2 + Cl-
In the catalysed
reaction the cobalt(II) ions are initially oxidised to Co(III) , the electrons released produce two OH-
ions
2Co2+ + OCl- + H2O 2Co3+
+ Cl- + 2OH-
the cobalt(III)
is subsequently reduced to Co(II), producing water and oxygen gas
2Co3+
+ 2OH- 2Co2+ + ½
O2 + H2O
Complexes
understood as consisting of a central metal atom or ion surrounded by a number
of ligands, defined as anions or molecules possessing lone pairs of
electrons. Coordination number . Experimental study of formation of complexes
of copper(II) and cobalt(II) with Cl-
and NH3 from the hexaquacations, viewed as ligand
replacement reactions. The use of stability
constants to determine the feasibility of ligand replacements. Candidates will not be expected to quote
names of complexes and only ligand replacement reactions involving monodentate
ligands will be expected in this module.
A complex
consists of a central metal atom or cation surrounded by ligands. Ligands are anions or neutral molecules
possessing a lone pair of electrons.
The formation of a complex involves the donation of a pair of electrons
from the ligand to the empty orbitals of the central metal atom or ion i.e.
dative covalent bonding.
The metal behaves
as a Lewis acid and the ligand as a Lewis base. The number of ligands surrounding the metal is known as the coordination
number.
e.g. [Co(H2O)6]2+
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H2O
2+
H2O H2O
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Co
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H2O
H2O
H2O
|
Complex |
Name |
Coordination
No |
|
[Co(H2O)6]2+ |
hexaaquacobalt
(II) |
6 |
|
[Ni(CO)4] |
tetracarbonylnickel
(0) |
4 |
|
[CoCl4]2- |
tetrachlorocobaltate (II) |
4 |
|
[Cu(NH3)4(H2O)2]2+ |
tetraamminediaquacopper (II) |
6 |
|
[Fe(CN)6]4- |
hexacyanoferrate(II) |
6 |
|
[Fe(CN)6]3- |
|
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[Al(H2O)6]3+ |
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[Pt(NH3)4]2+ |
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[PtCl4]2- |
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[CrCl(H2O)5]2+ |
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Transition metal
ions are relatively small and have a high charge density. In aqueous solution they attract water
molecules strongly. If a different ligand is added to a solution of a
transition metal complex in water, it will compete with the water molecules to
complex the metal. The reaction can be
regarded as a stepwise replacement of water ligands.
[M(H2O)6]n+ +
L ó
[M(H2O)5L]n+ + H2O
[M(H2O)5L]n+ +
L ó
[M(H2O)4L2]n+ + H2O
[M(H2O)4L2]n+ +
L ó
[M(H2O)3L3]n+ + H2O
etc.
This replacement
is easily observed because of the change in colour of the complex ion.
[Co(H2O)6]2+
(aq) + 4Cl- (aq) ó [CoCl4]2- (aq) + 6H2O
(l)
pink blue
Ligand
replacement reactions are equilibrium reactions. Each step will have a value for the equilibrium constant. We can write an equilibrium constant for the overall reaction e.g.
[Cu(H2O)6]2+ +
4NH3 ó [Cu(NH3)4(H2O)2]2+ +
4H2O
Kc =
[Cu(NH3)4(H2O)2]2+ [H2O]4
[Cu(H2O)6]2+ [NH3]4
As the reaction is carried out in water, its concentration effectively
remains constant, and the equilibrium expression can be modified as
Kst
= [Cu(NH3)4(H2O)2]2+ = 1 x 1013 dm12 mol-4
[Cu(H2O)6]2+ [NH3]4
where Kst
is the stability constant for the reaction.
The higher the
value of Kst the more stable the complex and the more readily it
will be formed when the ligand is added.
[Cu(H2O)6]2+ +
4Cl- ó [CuCl4]2- +
6H2O
Kst = [CuCl4]2-
=
1 x 105
[Cu(H2O)6]2+ [Cl-]4